# !/usr/bin/bash

weekday=$1

month=2 #`echo ${weekday:0:2}`
day=9  #`echo ${weekday:3:2}`
year=1947 #2013 #`echo ${weekday:6:4}`
weekday=1

for dayval in `cal $month $year | grep $day`
do
 [[ $day != $dayval ]] && weekday=$(($weekday + 1)) || break
done

echo "weekday is $weekday"

exit 0
